While the usual study of calculus involves derivatives and integrals, continuity plays an essential role in make sure these notions behave as expected.
We give the usual definition of continuity here, prove the continuity of polynomials, and state one visually intuitive theorem that takes surprisingly more effort than expected to prove. We will need this to prove the fundamental theorem of calculus.
Definition 1. Let be a real number
be a real valued function defined on
for some
. We say that
is continuous at
if
We say that is continuous on a subset
precisely when
is continuous at every
.
Using limit laws, it can be shown that continuous functions remain continuous under addition, subtraction, and multiplication. Division also works so long as the divisor has a nonzero function value. Rather trivially, it is not hard to prove that (i) constant functions are continuous, and (ii) is continuous in
. We prove (ii) for completeness.
Lemma. For any real , the function
is continuous at
.
Proof. Continuity can be reformulated in limits as
Setting ,
as required.
Let’s first define polynomials, whose continuity we aim to prove.
Definition 2. A non-zero real-valued function is a polynomial in
with degree
if there exist real constants
such that for any real
,
We are now ready to prove that polynomials are continuous.
Theorem 1. Any polynomial is continuous on .
Proof. Since the product of two continuous functions is continuous, the product of
copies of
is continuous as well. Since constant functions are continuous, all functions of the form
are continuous. Finally, since the sum of continuous functions is continuous,
is continuous.
We will state the extreme value theorem, which seems obvious, but whose proof we will omit.
Theorem 2 (Extreme Value Theorem). Let be continuous. Then there exist
such that for any
,
The extreme value theorem will be a crucial tool in studying differentiable functions, since the latter is continuous, and therefore inherit all properties of continuous functions.
Let’s establish a useful continuity result that will prove useful when discussing differentiation.
Theorem 3. Let be real-valued functions. Suppose
is continuous at
and
is continuous at
. Then the composite function
defined by
is continuous at .
Proof. Consider the computation
as .
—Joel Kindiak, 18 Oct 24, 1815H
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